Solving the transpose system is slightly more involved. In the usual formulation we traverse rows when solving a factored system, but here we can only access columns of the matrices and (at less than prohibitive cost). The key idea is to distribute each newly computed component of a triangular solve immediately over the remaining right-hand-side.

For instance, if we write a lower triangular matrix as , then the system can be written as . Hence, after computing we modify , and so on. Upper triangular systems are treated in a similar manner. With this algorithm we only access columns of the triangular systems. Solving a transpose system with a matrix stored in CRS format essentially means that we access rows of and .

The algorithm now becomes

for i = 1, n x_tmp(i) = x(i) end; for i = 1, n z(i) = x_tmp(i) tmp = pivots(i) * z(i) for j = diag_ptr(i)+1, row_ptr(i+1)-1 x_tmp(col_ind(j)) = x_tmp(col_ind(j)) - tmp * val(j) end; end; for i = n, 1 (step -1) y(i) = pivots(i) * z(i) for j = row_ptr(i), diag_ptr(i)-1 z(col_ind(j)) = z(col_ind(j)) - val(j) * y(i) end; end;The extra temporary

Mon Nov 20 08:52:54 EST 1995